Question 325370
A point on the outer edge of a wheel is 2.5 feet from the axis of rotation. If the wheel spins at a full rate of 2,640 revolutions per minute, how many miles will the point on the outer edge of the wheel travel in one hour? 
A 75pi b 100pi c 112pi d 120pi e 150pi 
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The point travels 5pi feet per revolution.
In one hour, the wheel will make 2640 rev/min * 60 min/hr = 158400 revs
The distance = 5pi*158400/5280
= 150pi miles