Question 325360
Graph the inequality on a plane 
2x + 3y (is less than or equal to) 6 
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1st: Graph the boundary of the inequality:
3y = -2x+6
y = (-2/3)x + 2
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{{{graph(400,300,-10,10,-10,10,(-2/3)x+2)}}}
That is the graph of the EQUALITY.
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2nd: Pick a test point that is not on the boundary.
Pick (0,0)
Test it in the INEQUALITY:
2*0 + 3*0 < 6
0 < 6
That is true.
So the graph of the INEQUALITY is the half-plane 
containing (0,0).
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{{{graph(400,300,-10,10,-10,10, y<(-2/3)x+2)}}}
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Cheers,
Stan H.