Question 325361
the present age of a women is three years more that three times the age of her daughter. 
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m = 3d
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three years hence, the womans age will be ten years more than twice the age of her daughter.
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(m+3) = 2(d+3)+10
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find their present ages.
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Substitute for "m" and solve for "d":
(3d+3) = 2(d+3)+10
3d+3 = 2d+6+10
d = 13 (daughter's age NOW)
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Since m = 3d, m = 39 (mother's age NOW)
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Cheers,
Stan H.