Question 325261
There are four green blocks and four red blocks in a bag. 
a What is the probability of selecting a red block, keeping it, then selecting
another red block?
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1st red: 4/8
2nd red: 3/7
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P(red/red) = (4/8)*(3/7) = 3/14
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b What is the probability of selecting a green block, replacing it, then selecting a red block?
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P(green/red) = (1/2)(1/2) = 1/4
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Cheers,
Stan H.
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