Question 37656
4OR+5A=200 & 3OR+4A=156 IF WE MULTIPLY THE FIRST EAUATION BY 3 AND THE SECOND BY 4 WE GET

12OR+15A=600 &
12OR+16A=624 AND SUBTRACT THESE TWO WE GET
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0OR-1A=-24 OR A=24 THEN 4OR+5*24=200 OR 4OR+120=200 OR 4OR=80 OR OR=80/4 OR 

OR=20 PROOF

4*20+5*24=200 OR 80+120=200 OR 200=200 & 3*20+4*24=156 OR 60+96=156 OR 156=156