Question 325093
{{{200/x+240/(x-20)=(200(x-20))/(x(x-20))+(240x)/(x(x-20))=(200x-4000)/(x(x-20))+(240x)/(x(x-20))=(200x-4000+240x)/(x(x-20))=(440x-4000)/(x(x-20))=(440x-4000)/(x^2-20x)}}}


So {{{200/x+240/(x-20)=(440x-4000)/(x^2-20x)}}}