<PRE><B>Question 324997</B>
How do you the sum of the first 850 odd numbers? 
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The 1st odd digit is one: a(1) = 1
The difference between each odd digit is d = 2
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To find the nth term of the sequence use a(n) = a(1) + (n-1)d
a(850) = 1+849(2) = 1699
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The sum of n terms of n terms of the sequance is s(n) = (n/2)(a(1)+a(n))
S(850) = (850/2)(1+1699+1)
S(850) = 425*850 = 361,250
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Cheers,
Stan H.
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