Question 324899
Find the slope of line 1,
{{{m=(y2-y1)/(x2-x1)=(1-0)/(3-0)=1/3}}}
Line 1 is then,
{{{y-0=(1/3)(x-0)}}}
{{{y=(1/3)x}}}
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Line 2 is,
{{{y-5=-(2/3)(x+1)}}}
{{{y=-(2/3)x-2/3+15/3}}}
{{{y=-(2/3)x+13/3}}}
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To find the intersection point, set the equations equal to each other,
{{{(1/3)x=-(2/3)x+13/3}}}
{{{x=13/3}}}
Then use either equation to solve for y,
{{{y=(1/3)(13/3)}}}
{{{highlight( y=13/9)}}}
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{{{drawing(300,300,-6,6,-6,6,grid(1),circle(0,0,.3),circle(3,1,.3),circle(-1,5,.3),circle(13/3,13/9,.3),graph(300,300,-6,6,-6,6,(1/3)x,-(2/3)x+13/3))}}}