Question 324761
{{{ graph( 300, 300, -3, 3, -10, 10,  6x^3-3x+11x^2-2)}}}
Looks like {{{highlight(x=-2)}}} is a zero, verify using the equation.
{{{6(-8)-3(-2)+11(4)-2=-48+6+44-2=0}}}
You can guess the other two or you can use polynomial long division to get the remaining quadratic equation.
{{{(6x^3-3x+11x^2-2)/(x+2)=6x^2-x-1}}}
You can then factor this quadratic,
{{{6x^2-x-1=(3x+1)(2x-1)}}}
Which yields,
{{{3x+1=0}}}
{{{3x=-1}}}
{{{highlight(x=-1/3)}}}
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{{{2x-1=0}}}
{{{2x=1}}}
{{{highlight(x=1/2)}}}