Question 37693
To do this problem you need Combinations and Permutations.
You know for combinations, the order of the object doesn't matter.  In this case, the order matters, so we will be using permutations. 

{{{nPr}}}
{{{n!/(n-r)!}}}

n equals the number of choices.  In this case, you have 6.
r equals the number of decisions yo make.  In this case, you have 6.
Plug your numbers in!

{{{6!/(0)!}}}

{{{0!}}} is ALWAYS equal to 1

{{{720/1}}}
Answer:{{{highlight(720)}}}

Hope this helps!