Question 324893
let the integers be x, x+2, x+4
..
10 times the first integer = 10x..............1
..
sum of second and third
= x+2 +x+4
=2x+6
6 times the sum 
6(2x+6)
=12x+36................2

equation 1 = equation 2
10x=12x +36
add -12x to both sides
10x-12x= 12x-12x+36
-2x=36
x= 36/-2
x=-18 . first integer
x+2 = -18+2=-16 second integer
..
x+4 = -18+4
=-14 third integer
...
Check 10x= 6(x+x+6)
10*-18=6(-18-18+6)
-180=-180

the integers are -18,-16,-14

you are right