Question 324887
Since {{{x^(-1)=1/x^1=1/x}}} and {{{x^(-2)=1/x^2}}}, this means that {{{2x^(-2) - x^(-1) - 1 = 0}}} can be rewritten as {{{2/x^2-1/x-1=0}}}



Now multiply EVERY term by the LCD {{{x^2}}} to get {{{2-x-x^2=0}}}. From there, rearrange the terms to get {{{-x^2-x+2=0}}} and multiply every term by -1 to get {{{x^2+x-2=0}}}. I'll let you use the quadratic formula to solve.