Question 324789
{{{2x^2-28x=50}}}
{{{2x^2-28x-50=0}}} <--- Subtract 50 from both sides
{{{x^2-14x-25=0}}} <--- Divide both sides by 2
Use the quadratic formula,
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (14 +- sqrt( 14^2-4*1*(-25) ))/2 }}} 
{{{x = (14 +- sqrt( 196+100))/2 }}} 
{{{x = (14 +- sqrt( 296))/2 }}} 
{{{x = (14 +- 2sqrt( 74))/2 }}} 
{{{highlight(x = 7 +- sqrt( 74)) }}}
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{{{drawing(300,300,-3,17,-50,50,grid(1), circle(7-sqrt(74),0,.4),circle(7+sqrt(74),0,.4), graph(300,300,-3,17,-50,50, 2x^2-28x-50))}}}