Question 324760
{{{ graph( 300, 300, -1, 3, -2, 2, 6x^3 -13x^2 + x + 2) }}} 
Looks like {{{x=2}}} is a zero.
Verify using the equation.
{{{6(2)^3-13(2)^2+2+2=48-52+4=0}}}
Yes, {{{x=2}}} is a zero.
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You can guess and verify on the other two roots or do polynomial long division to find the remaining quadratic (then factor or use quadratic formula),
{{{(6x^3-13x^2+x+2)/(x-2)}}}