Question 324740
{{{y=x^2+3x}}}
{{{y=x(x+3)}}}
To find the x-intercept, set {{{y=0}}} and solve for {{{x}}}.
{{{x(x+3)=0}}}}
Two solutions:
{{{x=0}}}
.
.
.
{{{x+3=0}}}
{{{x=-3}}}
(0,0)
(-3,0)
.
.
.
To find the y-intercept, set x=0 and solve for y.
{{{y=0(0+3)=0}}}
(0,0)