Question 37649
How many ways can joe select 3 movies to rent from the top 10 rentals?
I came up with 720, is this correct? The next question is: How many ways can joe select 3 movies to rent from the top ten rentals and arrange them in a triple feature? Thanks

1st: Here you are counting GROUPS of movies; you are counting combinations.
 10C3 = [10!]/[(10-3)!3!]= [10*9*8]/[1*2*3]= 120
2nd: Here you are counting ARRANGMENTS of the movies; these are permutations.
10P3= 10*9*8= 720
Cheers,
Stan H.