Question 324718
<font face="Garamond" size="+2">


Parallel lines have identical slopes, that is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \parallel\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ m_2]


Perpendicular lines have slopes that are negative reciprocals, that is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


Both of your equations are in slope-intercept form, hence the slopes are the coefficients on the *[tex \Large x] terms.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>