Question 324696
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Let *[tex \Large w] represent the width.  Then *[tex \Large l\ = 2w] represents the length.  The perimeter is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P\ =\ 2l\ +\ 2w\ =\ 2(2w)\ +\ 2w\ =\ 288]


Hence


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 6w\ = 288]


Solve for *[tex \Large w] for the width, then double it to get the length.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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