Question 324675
x^2 + 8x = 3
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x^2+8x-3 = 0
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Formula: x = [-b +-sqrt(b^2-4ac]/[2a}
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a = 1 ; b = 8 ; c = -3
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x = [-8 +- sqrt(64-4*1*-3)]/[2*1]
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x = [-8 +- sqrt(76)]/2
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x = [-8 +- 2sqrt(19)]/2
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x = [-4 +- sqrt(19)]
x = -4+sqrt(19) or x = -4-sqrt(19)
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Cheers,
Stan H.