Question 323414
5 Brown
6 Yellow
4 Blue
3 Green
2 Orange
20 Total
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P(1 Green)=3/20
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P(1st Yellow)=6/20
P(2nd Yellow)=5/19
P(3rd Yellow)=4/18
P(Y,Y,Y)=(6/20)(5/19)(4/18)=1/57
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P(1st Brown)=5/20
P(2nd Orange)=2/19
P(3rd Orange)=1/18
P(B,O,O)=(5/20)(2/19)(1/18)=1/684