Question 323798
The area of a triangle is ,
{{{A=(1/2)bh}}}
{{{(1/2)(3h-1)h=51}}}
{{{(3h-1)h=102}}}
{{{3h^2-h-102=0}}}
{{{(3h+17)(h-6)=0}}}
Only the positive answer makes sense for this problem.
{{{h-6=0}}}
{{{highlight(h=6)}}}
{{{b=3(6)-1}}}
{{{highlight(b=17)}}}