<PRE><B>Question 324573</B>
I am trying to complete the square. 
x(2x+3)-1=0
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2x^2 + 3x - 1 = 0
2(x^2 + (3/2)x) = 1
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Complete the square:
2(x^2 + (3/2)x + (3/4)^2) = 1 + 2(3/4)^2
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2(x+(3/4))^2 = 1+9/8
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2(x+(3/4))^2 = 17/8
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(x+(3/4))^2 = 17/16
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x+(3/4) = sqrt(17)/4 or x+(3/4) = -sqrt(17)/4
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x = (-3+sqrt(17))/4 or x = (-3-sqrt(17))/4
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Cheers,
Stan H.
</PRE>