Question 324556
 I just need to know if this is right and if not the right way to do it. 
[3÷(a²+a)]•[(2a+2)÷6]
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= [3÷(a(a+1))• [(2(a+1))÷(2•3)]
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Cancel factors that are common to 
a numerator and a denominator, such
as 3,2, and (a+1), to get:
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= 1/a
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Cheers,
Stan H.