Question 324458
Rewrite 25 s 5^2.

(5^2)^(2x - 1) = 5^(5x + 1)

5^(4x - 2) = 5^(5x + 1)

Since we now have the same base 5 on both sides, we simply bring down the exponents and solve for x.

4x - 2 = 5x + 1

Can you find x now?