Question 324430
{{{(2i)/(3-4i)=((2i)/(3-4i))*((3+4i)/(3+4i))}}}
{{{(2i)/(3-4i)=(6i+8i^2)/(9+12i-12i-16i^2)}}}
{{{(2i)/(3-4i)=(-8+6i)/(9+16)}}}
{{{(2i)/(3-4i)=-(8/25)+(6/25)i}}}