Question 324303
{{{ log((x+2))=1-log((x-1)) }}}
{{{log((x+2))+log((x-1))=1}}}
{{{log((x+2)(x-1))=1}}}
{{{(x+2)(x-1)=10}}}
{{{x^2-x+2x-2=10}}}
{{{x^2+x-2=10}}}
{{{x^2+x-12=0}}}
{{{(x+4)(x-3)=0}}}
Two solutions:
{{{x+4=0}}}
{{{x=-4}}}
This solution is not allowed since the log function requires positive arguments.
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{{{x-3=0}}}
{{{highlight(x=3)}}}