Question 324112
Let x=amount invested at 7%. Then, the amount invested at 10% would be 8000-x.

So, we have {{{.07x+.10(8000-x)=710}}}

{{{.07x+800-.10x=710}}}

{{{-.03x=-90}}}

{{{x=3000}}} invested at 7%, there is 5000 invested at 10%.