Question 323897
The measure of an angle is six more than twice the measure of its complement.  Find the measures of both angles.


Let angle be A


Then its complement  = 90 - A


Now, since the angle is six more than twice the measure of its complement, we'll have:


A = 2(90 - A) + 6


A = 180 - 2A + 6


3A = 186


A = {{{186/3}}} = {{{62^o}}}


Therefore, one angle is {{{highlight_green(62^o)}}} and the other is: {{{highlight_green(28^o)}}} ----- {{{90^o - 62^o}}}