Question 323800
The perimeter of a rectangle is 182 inches. The length exceeds the width by 21 inches. Find the length and the width. 


Let width be W


Since length exceeds width by 21", its length is: W + 21


Since perimeter = 182, and since perimeter = 2L + 2W, then we'll have: 


2(W + 21) + 2W = 182


2W + 42 + 2W = 182


4W = 140


Therefore, W, or width = {{{140/4}}} or {{{highlight_green(35)}}} inches, and 


L, or length = {{{highlight_green(56)}}} ----- (35 + 21)


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Check
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2W  + 2L = 182


2(35) + 2(56) = 182


70 + 112 = 182 (TRUE)