Question 323763
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It is the product of two conjugates:  *[tex \LARGE (a\ +\ b)(a\ -\ b)\ =\ a^2\ -\ b^2], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(8x^4\right)^2\ -\ \left(6\right)^2]


You can simplify for yourself.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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