Question 323759
{{{(27x^6+63x^5-81x^2)/(9x^2)=(27x^6)/(9x^2)+(63x^5)/(9x^2)-(81x^2)/(9x^2)=3x^4+7x^3-9}}}



So {{{(27x^6+63x^5-81x^2)/(9x^2)=3x^4+7x^3-9}}}