Question 323637
{{{S=sum(16/2^n,n=0,infinity)=16*(sum(1/2^n,n=0,infinity))}}}
{{{S=sum(16/2^n,n=0,infinity)=16*2}}}
{{{S=sum(16/2^n,n=0,infinity)=highlight(32)}}}
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There are 501 terms.
{{{S=(n(A1+An))/2}}}
{{{S=(501(500+1000))/2}}}
{{{highlight(S=375750)}}}