Question 322809
{{{((w^2-1)/(w-1)^2)*((w-1)/(w^2+2w+1))=( ((w-1)*(w+1))/(w-1)^2 )*( (w-1)/(w+1)^2)))}}}
{{{((w^2-1)/(w-1)^2)*((w-1)/(w^2+2w+1))=( (cross((w-1))*cross((w+1)))/cross((w-1)^2) )*( cross((w-1))/(w+1)^(cross(2))))}}}
{{{((w^2-1)/(w-1)^2)*((w-1)/(w^2+2w+1))=1/(w+1)}}}