Question 323585
One has 50% alcohol and 50% water 
other has 75% alcohol and 25% water.
Mixture = 8 liters of solution 60% alcohol and 40% water?
..
let 50% alcohol required be x liters
75% acohol required will be 8-x liters
Total mixture = 8 liters 60%
..
0.5x+0.75(8-x)=8*0.6
0.5x+6-0.75x=4.8
-0.25x=-1.2
x= -1.2/ -0.25
x=4.8 liters 50% alcohol
75% alcohol required = 3.2 liters