Question 37444
 x + 2y < 3 and 2x – 3y < 6
2y < 3 - x
y < 3/2 -(1/2)*x
3y >2x - 6
y > (2/3)x - 2
 {{{ graph( 300, 300, -10, 10, -10, 10, -(1/2)*x + 3/2, (2/3)*x - 2) }}}
The inequalities are satisfied by the region between the two
lines to the left of their intersection at (3,0)