Question 323332
Given:
{{{x^2yz + x + y }}}
and
x = 1, y= -3, and z = 3
.
Simply plug in the given values into the equation to get:
{{{1^2(-3)(3) + 1 + (-3) }}}
{{{1(-3)(3) + 1 + (-3) }}}
{{{1(-3)(3) + 1 - 3 }}}
{{{ (-3)(3) + 1 - 3 }}}
{{{ -9 + 1 - 3 }}}
{{{ -8 - 3 }}}
{{{ -11 }}}