Question 323260
{{{(5xy^-3)^-2(2x^3y^-2)^3}}}
I came up with 2x^7/5
{{{(5xy^-3)^-2(2x^3y^-2)^3}}}
= {{{(2x^3y^-2)^3/(5xy^-3)^2}}}
= {{{(8x^9y^-6)/(25x^2y^-6)}}}
= {{{(8x^9)/(25x^2)}}}
= {{{(8x^7)/(25)}}}