Question 37532
{{{log(3,(x+1)) - log(3,x) = log(3,4)}}}
log a/b = log a - log b
{{{log(3,(x+1)/x) = log(3,4)}}}
If the logs are equal, then the things we are taking the 
log of are equal
{{{(x + 1) / x = 4}}}
{{{x + 1  = 4x}}}
{{{3x = 1}}}
{{{x = 1/3}}}
check
{{{log(3,(x+1)) - log(3,x) = log(3,4)}}}
{{{log(3,4/3) - log(3,1/3) = log(3,4)}}}
{{{log(3,4) - log(3,3) - log(3,1) + log(3,3) = log(3,4)}}}
note that
{{{log(a,b/c) - log(a,d/e) = log(a,b) - log(a,c) - (log(a,d) - log(a,e)}}} 
{{{log(3,4) - 1 - 0 + 1 = log(3,4)}}}
checks OK