Question 322897
When the player first releases the basketball, the ball has not traveled any horizontal distance away from the player.  This means that at the point of release, d=0 meters.
Now plug that into the equation to find the height:
h = -0.09d² + 0.9d + 2
h = -0.09(0)² + 0.9(0) + 2
h= 2 meters
The ball is 2 meters off the floor when the player first releases it.