Question 322824
Let A be the amount of 80% solution, B the amount of 44% solution.
1.{{{A+B=320}}}
.
.
.
{{{80A+44B=53(320)}}}
2.{{{20A+11B=4240}}}
From eq. 1,
{{{A=320-B}}}
{{{20A=6400-20B}}}
Substitute into eq. 2,
{{{6400-20B+11B=4240}}}
{{{-9B=-2160}}}
{{{B=240}}}
Then from eq. 1,
{{{A+240=320}}}
{{{A=80}}}
.
.
.
80 ml of 80% solution and 240 ml of 44% solution.