Question 322815
Let {{{d}}} = number of dimes
Let {{{n}}} = number of nickels
given:
(1) {{{d + n = 40}}}
(2) {{{10d + 5n = 350}}} (in cents)
Multiply both sides of (1) by {{{5}}} and
subtract (1) from (2)
(2) {{{10d + 5n = 350}}}
(1) {{{-5d - 5n = -200}}}
{{{5d = 150}}}
{{{d = 30}}}
and
{{{30 + n = 40}}}
{{{n = 10}}}
There are 30 dimes and 10 nickels