Question 322793
We're given that has " a slope of -1/3", so {{{m=-1/3}}}. In addition, we're told that the line passes " through the point (6, -4)" which means that {{{x=6}}} and {{{y=-4}}}



{{{y=mx+b}}} Start with the general slope intercept equation. 



{{{-4=-(1/3)(6)+b}}} Plug in {{{m=-1/3}}}, {{{x=6}}} and {{{y=-4}}}



{{{-4=-2+b}}} Multiply {{{-1/3}}} and {{{6}}} to get {{{-6/3=-2}}}



{{{-4+2=b}}} Add 2 to both sides.



{{{-2=b}}} Combine like terms.



So {{{b=-2}}} which means that the equation of the line is {{{y=-(1/3)x-2}}}