Question 322756
Let A and B be the numbers.
1.{{{A+B=10}}}
2.{{{AB=-56}}}
Useing eq. 1,
{{{A=10-B}}}
Substitute into eq. 2,
{{{(10-B)B=-56}}}
{{{10B-B^2=-56}}}
{{{B^2-10B-56=0}}}
{{{(B-14)(B+4)=0}}}
Two solutions:
{{{B-14=0}}}
{{{B=14}}}
Then from eq. 1,
{{{A+14=10}}}
{{{A=-4}}}
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{{{B+4=0}}}
{{{B=-4}}}
Then from eq. 1,.
{{{A-4=10}}}
{{{A=14}}}
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14 and -4 are the two numbers.