Question 322742
{{{(1/9-1/y^2)/(1/3+1/y)=(3y*(1/9-1/y^2))/(3y*(1/3+1/y))}}}
{{{(1/9-1/y^2)/(1/3+1/y)=(y^2-9)/(3y^2+9y)}}}
{{{(1/9-1/y^2)/(1/3+1/y)=((y-3)(y+3))/(3y(y+3))}}}
{{{(1/9-1/y^2)/(1/3+1/y)=(y-3)/3y}}}
{{{(1/9-1/y^2)/(1/3+1/y)=1/3-1/y}}}