Question 322613
For this problem you are going to use distribution in multiplication:multiply the 1st number by the 3rd and 4th, add them, then multiply the 2nd number by the 3rd and 4th, add them.

(x^4-3)(2x+1)=
(x^4)*(2x)+(x^4)*(1)+(-3)*(2x)+(-3)(1)
2(x^5)+(x^4)-6x-3

Your answer is 2x^5+x^4-6x-3