Question 26887
(5-i)x+2-3i=(3-2i)x+3-i
5x-xi+2-3i=3x-2xi+3-i
5x-3x-xi+2xi=3-2-i+3i
2x+xi=1+2i
x(2+i)=1+2i
x=1+2i/2+i    multiply by 2-i/2-i
x=(1+2i/2+i)(2-i/2-i)
x=(1+2i)(2-i)/(2+i)(2-i)       (2+i)(2-i)= 4-i^2   replace i^2 by -1  4-(-1)=5
                               (1+2i)(2-i)=2+4i-i-2i^2 replace i^2 by -1
                                          =2+3i+2= 4+3i
x= 4+3i/5 or 4/5+3i/5

Answer x=4/5+3i/5