Question 322172
The equation is in vertex form, {{{y=a(x-h)^2+k}}} where (h,k) is the vertex.
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Direction of opening: Upwards, the coefficient of {{{x^2}}} term ({{{3}}}) is positive.
Vertex: ({{{4}}},{{{1}}})
The axis of symmetry contains the vertex:{{{x=4}}}
Minimum occurs at the vertex:{{{ymin=1}}}
Domain: ({{{-infinity}}},{{{infinity}}})
Range: ({{{1}}},{{{infinity}}})
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{{{drawing(300,300,-2,10,-2,10,grid(1),blue(line(4,-10,4,10)),circle(4,1,.3), graph(300,300,-2,10,-2,10 ,3(x-4)^2+1))}}}