Question 321878
I think the problem is,
{{{7v/8-(8v-4)/(5v-4)}}}
Use a common denominator {{{8(5v-4)}}}
{{{7v/8-(8v-4)/(5v-4)=(7v(5v-4))/(8(5v-4))-(8(8v-4))/(8(5v-4))}}}
{{{7v/8-(8v-4)/(5v-4)=((35v^2-28v)-(64v-32))/(8(5v-4))}}}
{{{7v/8-(8v-4)/(5v-4)=(35v^2-92v+32)/(8(5v-4))}}}