Question 321857
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Let *[tex \Large x] represent the number.


Twice the number:  *[tex \Large 2x]


4 less than the number:  *[tex \Large x\ -\ 4]


The sum of ...  *[tex \Large 2x\ +\ (x\ -\ 4)]


Is the same as:  *[tex \Large =]


The difference between -32 and the number: *[tex \Large (-32)\ -\ x]


Putting it all together:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ (x\ -\ 4)\ =\ (-32)\ -\ x]


Simplify and solve:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ (-32)\ +\ 4]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ -28]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -7]


Check:


Twice the number: -14


4 less than the number -11


The sum  -25


-32 - (-7) = -25 Checks.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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