Question 321844
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ 2\sqrt{5L}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2\sqrt{5L}\ =\ r]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{5L}\ =\ \frac{r}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5L\ =\ \frac{r^2}{4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \L\ =\ \frac{r^2}{20}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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